An online merchant sells products that can be classified into the following non-intersecting categories: video games, electronics and clothing.In any given week, it is estimated that twice as many video games are sold compared to clothing items. However, the number of electronic items sold would be two-thirds of the number of video games sold, less one-fifth of the number of clothing items sold. A total of five items were independently sold in the past week.What is the probability that the five items consisted of three video games, one electronic item and one clothing item?A. 0.03B. 0.06C. 0.08D. 0.12E. 0.15

0.15 ( E )

Step-by-step explanation:

Assuming

video game to be : V

electronics : E

clothing : C

From the content of the question

V = 2c

hence E = 2/3 V - 1/5 C  

              = 2/3 ( 2c ) -  1/5 c

              =

therefore : V = 2c  and E =  17c / 15

assuming the number of clothing ( c ) = 15

V = 2*15 = 30  and E = ( 17 *15 ) / 15 = 17

Total number of items sold =  V + C + E = 30 + 15 + 17 = 62

from here we can determine the probability that of the five items independently sold that there are 3 video game, 1 electronic item and 1 clothing item

attached below is the remaining part of the solution

1 and 3

Step-by-step explanation:

Step 1 is clearly elaborated.  Tax is impliedd on the discounted price.

In step 3, the steps of deductions are skipped.

Like 1 + 10% = 110% and 1 - 20% = 80%

Step 2 is simply wrong. Because the percentages are implied on different values.