sakugrey
29.09.2019 •
Mathematics
An ordinary fair die is a cube with the numbers 1 through 6 on the sides. imagine that such a die is rolled twice in succession and that the faces of the 2 rolls are added together. this sum is recorded of single trial of a random experiment. event a: the sum is greater than 6 event b the sum is divisible by 6
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Ответ:
A. 5/9 B. 1/6.
Step-by-step explanation:
Total possible events = 6*6 = 36.
A. The possible combinations for the sum being <= 6 are:
1 ,1 2,2 3,3 1,2 1,3 1,4 1,5 2,1 2,3 2,4 3,1 3,2 3,3 4,1 4,2 5,1
= 16
So Probability of Sum > 6 = (36-16) / 36
= 20/36
= 5/9.
B. Possible combinations where the sum is divisible by 6 are
3,3 2,4 4,2 1,5 5,1. 6,6 = 6.
So the required probability = 6/36
= 1/6.
Ответ: