aliami0306oyaj0n
02.09.2019 •
Mathematics
And ! (asap)
a freight train left seoul and traveled north at an average speed of 15.6 km/h. a passenger train left 3.9 hours later and traveled in the same direction but with an average speed of 39 km/h. how long did the freight train travel before the passenger train caught up?
( and explain)
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Ответ:
(we can just subtract this because they are traveling in the same direction) - this means that it's as if the slower train (the freight) was in place and the passenger train was traveling at 23.4 km/h
No, the freighter left 3.9 hours earlier, during which it traveled
15.6*3.9=60.84 km
So they will meet when the passenger train will catch up on those 60.84 km.
It does it with 23.4 km/h so it will need:
So the freighter will be travellinf for 2.6 more hours than the other train - a total of (2.6+3.9=6.5) 6.5 hours!
Ответ:
31% × 96.000.000= 29.760.000