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julianbeaver76
21.10.2019 •
Mathematics
Anita’s sister invested all of $6000 at 4% and at 6%. if the annual return on the 6% investment is $15 more than the annual return on the 4% investment, find how much is invested at the latter rate.
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Ответ:
x (4%)
y (6%)
x+y=6000
0.06y=0.04x+15
The answer would be 2550, so $2550.
Ответ:
$3,450
Step-by-step explanation:
The amount invested in the two portfolios sums up to $6,000. Given that the annual return on the 6% investment is $15 more than the annual return on the 4% investment, then if the annual return on the 4% investment is I, the returns on the 6% investment will be
= I + 15 (in $)
the return on investment may be computed using the simple interest formula
I = PRT/100
Where I is the return, P is the amount invested, R is the rate of returns and T is time in years.
let the amount invested in the 4% investment be D, then the amount invested in the other will be
= 6000 - D
Considering the two investments
I = D * 4 * 1/100
100I = 4D
D = 25I
I + 15 = (6000 - D) * 6 * 1/100
100I + 1500 = 36000 - 6D
100I + 6D = 34500
4D + 6D = 34500
10D = 34500
D = $3,450
Ответ:
third one is your answer