Mathematics: Another math problem. Can you solve it? I can t... For a good answer I ll make it The Best I hope you can help me... Thanks

Another math problem. Can you solve it? I can t...

Ответ:

sierravick123owr441

30.01.2022

Mathematics

$\boxed{\sf \ \ \ 10^2+11^2+12^2=13^2+14^2 \ \ \ }$

Step-by-step explanation:

Hello,

let's note a a positive integer

5 consecutive integers are

a+1

a+2

a+3

a+4

so we need to find a so that

$a^2+(a+1)^2+(a+2)^2=(a+3)^2+(a+4)^2\\\\a^2+a^2+2a+1+a^2+4a+4=a^2+6a+9+a^2+8a+16\\\\3a^2+6a+5=2a^2+14a+25\\\\a^2-8a-20=0\\\\(a+2)(a-10)=0\\\\a = -2 \ or \ a = 10\\$

as we are looking for positive integer the solution is a = 10

do not hesitate if you have any question

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Another math problem. Can you solve it? I can't... For a good answer I'll make it 'The Best' I hope you can help me... Thanks

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