Aparallelogram has an area of 120 square units. its perimeter is between 40 and 50 units. list two possible dimensions for the parallelogram.

The dimensions are:

10 units and 12 units

10 units and 14 units

Step-by-step explanation:

∵ The area of the parallelogram is 120 units²

∵ 40 < perimeter of it < 50

∵ Perimeter of it = 2(b1 + b2)

∴ 40 < 2(b1 + b2) < 50 ⇒ ÷ 2

∴ 20 < b1 + b2 < 25

∴ b1 + b2 = 21 , 22 , 23 , 24

* We can chose any sum of them

∵ The area of the parallelogram = b1 × h1 = b2 × h2

∵ b1 × h1 = 120

∴ We can chose b1 = 10 so h1 = 12 ⇒ b2 = 11 , 12 , 13 , 14

  Or we can chose b1 = 12 so h1 = 10 ⇒ b2 = 9 , 10 , 11

∴ We can chose any two dimensions above

Option 2,3 and 4 are correct.

Step-by-step explanation:

To find : Which terms could be used as the first term of the expression below to create a polynomial written in standard form? Check all that apply.

Solution :

The polynomials in standard form is written from higher degree to lower degree i.e. in descending order.

The given polynomial has degree 6: , and it can be ordered respect any of the two variables either r or s.

Adding a new term as first term needs to have degree equal or greater than 6.

1) cannot use as first term because its degree is less than 6.

2) it can be use as degree is 9.

is the standard form.

3) it can be use as degree is 10.

is the standard form.

4) it can be use as degree is 6.

is the standard form.

Therefore, Option 2,3 and 4 are correct.