Mathematics: Apartment A has two floors 30 feet wide and 40 feet long and a 15-foot-long by 30-foot-wide third floor. Apartment B has two floors that are both 40 feet long and 40 feet wide. The cost of both is $55 per square foot. What is the difference in total cost between Apartment A and Apartment B ?

YesStep-by-step explanation:...

Apartment A has two floors 30 feet wide and 40 feet

morenodonaldo762

19.01.2022

$19,250 is the difference in total cost between Apartment "A" and Apartment "B".

Step-by-step explanation:

Apartment A

Length of first floor = l = 40 ft

Width of the first floor = w = 30 ft

Area of first floors = A = lw = $40ft\times 30 ft=1200 ft^2$

Area of first floors = Area of second floor = 1200 ft^2

Length of third floor = l' = 15 ft

Width of the third floor = w' = 30 ft

Area of third floors = A' = l'w' = $15 ft\times 30 ft=450 ft^2$

Total area of the floor of apartment A = T

T = A +A +A' = 1200 ft^2+1200ft^2+450 ft^2=2850 ft^2

The cost of floor = $55 per square foot

Total Cost of apartment A :

C = $55 \$/ft \times 2850 ft^2 =\$156,750$

Apartment B

Length of first floor = L = 40 ft

Width of the first floor = W = 40 ft

Area of first floors = a = LW = $40ft\times 40 ft=1600 ft^2$

Area of first floors = Area of second floor = 1600 ft^2

Total area of the floor of apartment B = T'

T' = a + a = 1600 ft^2+1600ft^2=3200 ft^2

The cost of floor = $55 per square foot

Total Cost of apartment B :

C' = $55 \$/ft \times 3200 ft^2 =\$176,000$

The difference in total cost between Apartment "A" and Apartment "B"L:

C' - C = $176,000 - $156,750 = $19,250

$19,250 is the difference in total cost between Apartment "A" and Apartment "B".

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