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04.01.2020 •
Mathematics
Arandom sample of 250 men yielded 175 who said they'd ridden a motorcycle at some time in their lives, while a similar sample of 215 women yielded only 43 that had done so. find a 99% confidence interval for the difference between the proportions of men and women who have ridden motorcycles.
a. 5 ± .103
b. 5 ± .085
c. 5 ± .112
d. 4688 ± .085
e. 5 ± .078
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Ответ:
Option a is right
Step-by-step explanation:
Given that a random sample of 250 men yielded 175 who said they'd ridden a motorcycle at some time in their lives, while a similar sample of 215 women yielded only 43 that had done so.
For proportions since binomial and sample size large we can use z critical values.
Sample I II
N 250 215 465
X 175 43 218
p 0.7 0.2 0.4688
p difference = 0.5
Std error of difference =![\sqrt{p(1-p)(\frac{1}{n_1}+ \frac{1}{n_2} }\\=\sqrt{0.4688*0.5312)(\frac{1}{250} + \frac{1}{215} )}\\=0.0409](/tpl/images/0441/8311/abade.png)
Margin of error for 99% = 2.58*std error = 0.105
Confidence interval 99% = (0.5±0.105)
Option a is right.
Ответ:
jourdynd16 dose not know how to do his math do not trust him he is stupid at math he got the answer of google
Step-by-step explanation: