Arectangle has a length of 10 inches less than 8 times its width. if the area of the rectangle is 558 square inches, find the length of the rectangle.

Let x = width length = 5x -10  (10 ft less than 5 times width) A = l * w A = (5x-10)*x 2640 = 5x2 -10x 5x2 -10x -2640=0 divide by 5 x2 -2x - 528 = 0 (x-24)(x+22)=0 x-24=0 x=24   width (the other factor would give us a negative length) length = 5*24 -10 length = 110

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