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jaida03
22.09.2019 •
Mathematics
Arectangular rug has an area of 15 square feet. its perimeter is 16 feet. what are the dimensions of the rug?
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Ответ:
30+2h^2=16h. manipulate the equation so the resulting quadratic is obvious (just set one side 0) and rearrange terms. so then we have 2h^2-16h+30=0. factor out the 2 to make the quadratic easier to solve ie..2(h^2-8h+15)=0. now solving the quadratic gives 2(h-5)(h-3)=0 so h=3 or h=5 just pick one and substitute it for h in the perimeter equation. choosing 5 for h we get 2b+2(5)=16 which gives 2b+10=16 which gives 2b=6 so b = 3. with b=3 and h=5 for each equation we get 2(b)+2(h)=16 = 2(3)+2(5) =16 this is correct. substituting the values into the area equation gives b*h=15 = 3*5=15 this also checks out so the dimensions of the rug are 3x5.
Ответ:
Step-by-step explanation:
let's try a:
-4*4x-4*(-17) - expand the distributing terms
-16x-4*(-17) - simplify
-16x-(-68) - simplify again
-16x+68 - remove parentheses
-16x+68 does not equal to 16x-68
lets try b:
-28x+3... dont know what u mean
lets try c:
13-34 first
-21
lets try d:
0-17
-17
lets try e:
-2x+(8-8)
-2x
fortunally dont know what you mean.