Aroad trip of 400 miles require a total of 8 hours to drive. for the first portion of the trip, an average speed of 63 miles per hour was maintained; on the last portion of the trip, the average speed was only 443 miles per hour due to highway construction project. how much time, in hours, to the nearest tenth of an hour, was spent driving at each of the two speeds, and what was the total time for the entire trip?

2.8 hours at 63 mph 5.2 hours at 43 mph Total time spent driving = 8.0 hours. I'm assuming based upon context that your value of 443 miles per hour is a typo and the correct value is 43 miles per hour. The solution provided is for the two speeds of 63 mph and 43 mph. First make an expression detailing what you know. X = duration spent at 63 mph (8 - X) = duration spent at 43 mph 63X + 43(8-X) = 400 Solve for X 63X + 43(8-X) = 400 63X + 344 - 43X = 400 63X - 43X = 56 20X = 56 X = 2.8 So you spent 2.8 hours at 63 mph and 8-2.8 = 5.2 hours at 43 mph

to add: align your decimal and add just like you would regualar 2 or more digit numbers

To subtract: Write down the two numbers, one under the other, with the decimal points lined up. Add zeros so the numbers have the same length. Then subtract normally, remembering to put the decimal point in the answer.

To multiply: Multiply normally, ignoring the decimal points. Then put the decimal point in the answer - it will have as many decimal places as the two original numbers combined