Assume that when blood donors are randomly selected, 45% of them have blood that is Group O (based on data from the Greater New York Blood Program). 1. If the number of blood donors is n = 16 equation, find the probability that the number with Group O blood is equation x = 6.
2. If the number of blood donors is n = 8, find the probability that the number with group O is x = 3.
3. if the number of blood donors is n = 20, find the probability that the number with group O blood is x = 16.
4. if the number of blood donors is n = 11, find the probability that the number with group O blood is x = 9.

1. 0.1684 = 16.84%.

2. 0.2568 = 25.68%

3. 0.0013 = 0.13%

4. 0.0126 = 1.26%.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have blood that is Group O, or they do not. The probability of a person having blood that is Group O is independent of any other person, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

45% of them have blood that is Group O

This means that

Question 1:

This is P(X = 6) when n = 16. So

So 0.1684 = 16.84%.

Question 2:

This is P(X = 3) when n = 8. So

So 0.2568 = 25.68%.

Question 3:

This is P(X = 16) when n = 20. So

So 0.0013 = 0.13%.

Question 4:

This is P(X = 9) when n = 11. So

So 0.0126 = 1.26%.