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19.09.2019 •
Mathematics
Asurvey determines that mint chocolate chip is the favorite ice cream flavor of 6% of consumers. an ice cream shop determines that of 190 customers, 15 customers stated their preference for mint chocolate chip. find the p-value that would be used to determine if the percentage of customers who prefer mint chocolate chip ice has increased at a 5% level of significance. p-value:
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Ответ:
0.1356661
Step-by-step explanation:
Let p be the population proportion.
By the given information, we have
Null Hypothesis:![H_0: p=0.06](/tpl/images/0243/7918/58a2b.png)
Alternative Hypothesis :![H_1: p0.06](/tpl/images/0243/7918/bebc2.png)
Since , the alternative hypothesis is right-tailed , then the test is a right -tailed test.
Given : Sample size : n= 190
Number of customers stated their preference for mint chocolate chip : 15
The , the sample proportion :![\hat{p}=\dfrac{15}{190}\approx0.079](/tpl/images/0243/7918/1a6aa.png)
Test statistic for proportion:
i.e![z=\dfrac{0.079-0.06}{\sqrt{\dfrac{0.06\cdot0.94}{190}}}\approx1.10](/tpl/images/0243/7918/750c5.png)
By using the standard normal distribution table for z-score , we have
P-value for right tailed test :![P(Zz)=1-P(Z](/tpl/images/0243/7918/44fab.png)
i.e.![P(Z1.10)=1-P(Z](/tpl/images/0243/7918/19eb2.png)
Ответ:
0.1356661
Step-by-step explanation:
A survey determines that mint chocolate chip is the favorite ice cream flavor of 6% of consumers. An ice cream shop determines that of 190 customers, 15 customers stated their preference for mint chocolate chip. Therefore, the P-value that would be used to determine if the percentage of customers who prefer mint chocolate chip ice has increased at a 5% level of significance is 0.1356661.
Ответ:
The solution is
and ![x=-0.5](/tpl/images/0469/3875/bfc2f.png)
Step-by-step explanation:
The expression is![2x(x+1.5)=-1](/tpl/images/0469/3875/84591.png)
Multiplying the term
by
, we get,
Adding both sides by 1,
Taking factor, we get,
Equating the factors to 0,
Thus, the smaller value is![x=-1](/tpl/images/0469/3875/66413.png)
The solution is
and ![x=-0.5](/tpl/images/0469/3875/bfc2f.png)