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misst002
14.03.2020 •
Mathematics
At the movie theatre, child admission is $5.20 and adult admission is $9.00. on Monday, 132 tickets were sold for a total sales of $994.20. how many child tickets were sold that day?
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Ответ:
That day 51 child tikets were sold
Step-by-step explanation:
To do this problem we have to make 2 equations, one that represents the number of entries and the other that represents the money
x = child tickets
y = adult tickets
x + y = 132
x * $5.20 + y * $9.00 = $994.20
First we have to solve for the x in the first equation
x + y = 132
x = 132 - y
Now we replace the x with (132 - y) in the second equation
x * $5.20 + y * $9.00 = $994.20
(132 - y) * 5.20 + y * 9.00 = 994.20
686.4 - 5.2y + 9y = 994.2
-5.2y + 9y = 994.2 - 686.4
3.8y = 307.8
y = 307.8/3.8
y = 81
We replace y with its value in the first equation
x = 132 - y
x = 132 - 81
x = 51
That day 51 child tikets were sold
Ответ:
51 child tickets were sold that day.
Step-by-step explanation:
Let x represent the number of child admission tickets that were sold on Monday.
Let y represent the number of child adult tickets that were sold on Monday.
On Monday, 132 tickets were sold. It means that
x + y = 132
At the movie theatre, child admission is $5.20 and adult admission is $9.00. On Monday, the total sales was $994.20. This means that
5.2x + 9y = 994.2- - - - - - - - - - - -1
Substituting x = 132 - y into equation 1, it becomes
5.2(132 - y) + 9y = 994.2
686.4 - 5.2y + 9y = 994.2
- 5.2y + 9y = 994.2 - 686.4
3.8y = 307.8
y = 307.8/3.8
y = 81
x = 132 - y = 132 - 81
x = 51
Ответ:
7
Step-by-step explanation: