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princessammarah4731
24.09.2019 •
Mathematics
Atree trunk has a height of 30 feet and a radius of 2.5 what is the volume of the tree trunk
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Ответ:
L.) 589![ft^{3}](/tpl/images/0259/3592/60ebd.png)
Step-by-step explanation:
We can automatically asume that a Tree trunk is a cylinder. so the formula to find the volume of a cylinder is
So we have to substitue the values.
3.14 x (2.5 squared) x 30 = V
rewrite
3.14 x 6.25 x 30 = V
19.625 x 30 = 588.75
Your exact volume is 588.75
But we can round it. so therfore your answer is L.) 589 ![ft^{3}](/tpl/images/0259/3592/60ebd.png)
Hope this helped! Please mark a brainliest! Thanks!
Ответ:
The locations of A' and B' are A' (0, 6) and B' (6, 0), lines f and f' are
parallel ⇒ last answer
Step-by-step explanation:
* Lets explain how to solve the problem
- A dilation is a transformation that changes the size of a line segment.
- It can become larger or smaller
- The scale factor, measures how much larger or smaller
the image will be
- If the scale factor greater than 1, then the image will be larger
- If the scale factor between 0 and 1, then the image will be smaller
- The image of any point (x , y) by dilation about the origin by scale
factor k is (kx , ky)
- The line NOT passing through the center of the dilation is parallel to
its image
* Lets solve the problem
- Line f has two points A (0 , 2) and B (2 , 0)
- Line f dilate by scale factor 3 with center of dilation at the origin
- f' is the image of line f after dilation has points A' and B' whose the
images of A and B after dilation
∵ The scale factor is 3
∵ A = (0 , 2) and B = (2 , 0)
∴ A' = (0 × 3 , 2 × 3) = (0 , 6)
∴ B' = (2 × 3 , 0 × 3) = (6 , 0)
∴ Points A' and B' located at (0 , 6) and (6 , 0)
∵ Line f NOT passes through the origin point (center of dilation)
∴ Line f is parallel to its image f'
∴ Lines f and f' are parallel
* The locations of A' and B' are A' (0, 6) and B' (6, 0), lines f and f'
are parallel