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niti1409
19.07.2019 •
Mathematics
Atriangular banner has an area of 315 in^2
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Ответ:
area of larger triangle = 560 in²
Explanation:
We are given that the ratio between the side length of the larger triangle to the smaller one is 4:3
We can use this information to get the ratio between their areas.
To get the ratio between the areas, we will simply square the ratio between the side lengths as follows:
area of large triangle : area of small triangle
(4)² : (3)²
16 : 9
We are given that the area of the small triangle is 315 in², therefore, we can use cross multiplication to get the area of the large triangle as follows:
area of large triangle : area of small triangle
16 : 9
?? : 315
area of large triangle = (315*16) / 9
area of large triangle = 560 in²
Hope this helps :)
Ответ:
The description of the 6 parts of the right triangle ABC are as follows;
The legs of the right triangle are side "a" and side "b"
The hypotenuse side of the right triangle is side "c"
The acute angles are ∠A and ∠B
The 90° angle is ∠C
The description of the 6 parts are therefore given as follows;
1) A; ∠A is the acute angle opposite side "a" and ∠A is formed between the hypotenuse side "c" and the leg "b"
2) B; ∠B is the acute angle opposite side "b" and ∠B is formed between the hypotenuse side "c" and the leg "a"
3) C; ∠C is the 90° angle (right angle) opposite the hypotenuse side "c" and ∠C is formed between the the two legs "a" and "b"
4) a; Side "a" is one of the two legs of the right triangle ΔABC and it is the leg opposite to ∠A
5) b; Side "b" is one of the two legs of the right triangle ΔABC and it is the leg opposite to ∠B
6) c; Side "c" is the hypotenuse side of the right triangle ΔABC and it (the hypotenuse side) is (all the time) the longest side of the right triangle and it is the leg opposite to ∠A
Step-by-step explanation: