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wycentliver1859
27.11.2020 •
Mathematics
Bacteria of species A and species B are kept in a single environment, where they are fed two nutrients. Each day the environment is supplied with 10,560 units of the first nutrient and 31,510 units of the second nutrient. Each bacterium of species A requires 2 units of the first nutrient and 5 units of the second, and each bacterium of species B requires 1 unit of the first nutrient and 6 units of the second. What populations of each species can coexist in the environment so that all the nutrients are consumed each day? Incorrect: Your answer is incorrect. Of species A
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Ответ:
We require 4,550 of species A and 1,460 of species B that can coexist in the environment so that all the nutrients are consumed each day
Step-by-step explanation:
Let n₁ be the population of A required and n₂ be the population of B required.
Now we require 2 units of the first nutrient for species A and one unit of the first nutrient for species B. The total nutrients required by species A is 2n₁ and that by species B is 1n₂ = n₂. So, the total nutrients required by both species A and B is 2n₁ + n₂. Since this equals the quantity of the first nutrient which is 10,560, then 2n₁ + n₂ = 10,560 (1)
Now we require 5 units of the second nutrient for species A and 6 units of the second nutrient for species B. The total nutrients required by species A is 5n₁ and that by species B is 6n₂. So, the total nutrients required by both species A and B is 5n₁ + 6n₂. Since this equals the quantity of the first nutrient which is 31,510, then 5n₁ + 6n₂ = 31,510 (2).
So, we have two simultaneous equations which we would solve to find the populations of A and B which satisfy both equations.
2n₁ + n₂ = 10,560 (1)
5n₁ + 6n₂ = 31,510 (2)
From (1) n₂ = 10,560 - 2n₁ (3)
Substituting equation (3) into (2), we have
5n₁ + 6(10,560 - 2n₁) = 31,510
expanding the brackets, we have
5n₁ + 63,360 - 12n₁ = 31,510
collecting like terms, we have
5n₁ - 12n₁ = 31,510 - 63,360
simplifying, we have
- 7n₁ = -31,850
dividing both sides by -7, we have
n₁ = -31,850/-7
n₁ = 4,550
Substituting n₁ = 4,550 into (3), we have
n₂ = 10,560 - 2(4,550)
n₂ = 10,560 - 9,100
n₂ = 1,460
So, we require 4,550 of species A and 1,460 of species B that can coexist in the environment so that all the nutrients are consumed each day
Ответ:
a <= 3
Step-by-step explanation: