Bob has to interview 4 different candidates. He has to schedule each of them at different times throughout the day. How many different ways can he schedule the candidates?

 24

Label the time slots as A,B,C,D

For time slot A, he has 4 candidates to pick from. Then for time slot B he has 3 choices left (he doesn't want to interview the same person again), and C has 2 choices, with D having just one choice. Effectively we start at 4 and count our way down to 1. We will multiply these values out.

Overall, Bob has 4*3*2*1 = 24 different ways to arrange the candidate interviews. This is known as a permutation because order matters.

Step-by-step explanation: so for the first one you have your equation 18+4(m-3)+4m you take the second part and do 2(9+2(m-3)+2m) then after that you get 2(9+2m-6+2m)  and you get you first answer 2(3+4m)

Your second probelm 6+8m you have your equation 18+4(m-3)+4m  you do 18+4m-12+4 and you subtract all th likes terms so you get 6+8m

Hope this helps!