20jessicacabriales
12.09.2021 •
Mathematics
Can anyone help? Will give + 22 pts .
Question : A woman has a total of 9,000 to invest. She invest parts of the money in an account that pays 8% per year and the rest in an Account that pays 10% per year. if the interest earned in the first year is $800, how much did she invest in each account?
She invested $___ at 8% and $___ at 10%
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Ответ:
0.08*x + 0.09*(9000-x) = 750 dollars
0.08x + 810 - 0.09x = 750
-0.01x = 750 - 810 = -60 > x = %28-60%29%2F%28-0.01%29 = 6000.
Answer. $6000 was invested at 8%. The rest 9000-6000 = 3000 dollars were invested at 9%.
Check. 0.08*6000 + 0.09*3000 = 480 + 270 = 750 dollars. ! Correct !
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Ответ: