Can anyone help with this problem

9514 1404 393

Step-by-step explanation:

For a quadrilateral in which the diagonals cross at right angles, such as a rhombus or kite, the area can be found as half the product of the diagonals.

For the purpose here, we can ignore the factor of 1/2, which is the same for both, and simply consider the products of the diagonals.

Kite A has an area proportional to (30 in)(30 in) = 900 in².

Kite B has an area proportional to (20 in)(40 in) = 800 in².

Kite A has a larger area, so will use more paper.

__

Only Rudy knows why he chose answer C. Perhaps he guessed, rather than doing any math.

A. Kite A

Step-by-step explanation:

To determine which of the two kites will use need more paper to make, find the area of each kite.

Kite A:

Area = (d1*d2)/2

d1 = 30 in.

d2 = 30 in.

Area of kite A = (30*30)/2 = 450 in.²

Kite B:

Area = (d1*d2)/2

d1 = 20 in.

d2 = 40 in.

Area of kite B = (20*40)/2 = 400 in.²

✅Kite A will use more paper to make because it has a greater area of 450 in.² than Kite B (400 in.²).

So, Ruby was wrong. He most likely didn't calculate the area of both kites correctly.

11183333.3333

Step-by-step explanation:

6.71x100000000=671000000

÷

60= 11183333.3333