Can i get a little on the problem?
the bear population increases at a rate of 3% each year. there are 1462 bears this year. how many bears will there be in 10 years?

a.) 1506

b.) 2024

c.) 1598

d.) 1965

This question explores something known as exponential growth, and is often used to determine compound interest after a period of time.

We can use equation

y = xr^n

Where y is the value after n years, x is the initial value and r is the percentage growth each year.

By substituting

1462 * 1.03^10

We get a value that rounds to 1965, so your answer is D.

I suggest you look at exponential growth and decay on khanacademy, they explain it very well!

(-3,-7)

Step-by-step explanation: