Mathematics: Can someone me with 13-3/4x 13

To put the expressions in order from least value to greatest, we have to plug in the values for a and b first. Then, we must follow order of operations (parentheses, exponents, multiply, divide, add, subtract) to evaluate the expressions. Here s how:a = 2, b = 5Farthest left:The value for the expression to the farthest left is 27.Middle left:The value for the expression to the middle left is 4.Middle right: The value for the expression to the middle right is 17.Farthest right:The value for the expression...

Can someone me with 13-3/4x 13 - id1334131199717, nepats222

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briancastrodiaz10

26.02.2020

Mathematics

To put the expressions in order from least value to greatest, we have to plug in the values for a and b first. Then, we must follow order of operations (parentheses, exponents, multiply, divide, add, subtract) to evaluate the expressions. Here's how:

a = 2, b = 5

Farthest left:
$50-b^{2} +a \\ 50- 5^{2} +2 \\ 50-25+2 \\ 25+2 \\ 27$
The value for the expression to the farthest left is 27.

Middle left:
$a*(b-3) \\ 2*(5-3) \\ 2*(2) \\ 4$
The value for the expression to the middle left is 4.

Middle right:
$a^{2}*3+b \\ 2^{2} *3+5 \\ 4*3+5 \\ 12+5 \\ 17$
The value for the expression to the middle right is 17.

Farthest right:
$b^{2}-10 \\ 5^{2} -10 \\ 25-10 \\ 15$
The value for the expression to the farthest right is 15.

Now, we can order the values (27, 4, 17, and 15) from least to greatest:
4<15<17<27
Since we know which expressions equal those values, we can swap them in and order them appropriately:
$(a*(b-3)) \ \textless \ (b^{2}-10 ) \ \textless \ (a^{2}*3+b) \ \textless \ (50-b^{2} +a)$

Therefore, the answers are:
1. a*(b-3)

2. $b^{2}-10$
3. $a^{2}*3+b$
4. $50-b^{2} +a$

Hope this helps!

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Can someone me with 13-3/4x> 13

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