Can you Help me please :/

(-2, 1)

Step-by-step explanation:

Given:

2x+8y=4...(1)

6x-y=-13...(2)

You would want to have an x or a y value that equals the same in both equations. In this case, we can multiply equation 1 by 3 so that both x's in each equation equal 6x.

(2x+8y=4) x 3...(1)

6x-y=-13...(2)

becomes...

6x+24y=12...(3)

6x-y=-13...(4)

As you can see here, both x's in this equation are equal.

Now we will be combining these equations together. Take the equal x values and make sure they will equal 0. You do that by either subtracting the entire equation or adding it. In this problem, we will be subtracting it because 6x-6x=0

(6x+24y=12) - (6x-y=-13) = 25y =25

Now that we can solve for y separately, 25y=25   y=1

To solve for x, just substitute y into one of the original equations (equations 1 or 2). For this problem, I'll use equation 1.

6x-y=-13

6x-1=-13

6x=-12

x=-2

(This is what I got for my answer and here is the explanation. I apologize if my answer is incorrect. If someone notices a mistake in my answer, please correct me, thank you and have a nice day!)

AB = DE:

5x + 2 = 8x - 10

Subtract 5x from both sides:

2 = 3x -10

Add 10 to both sides:

3x = 12

Divide both sides by 3:

x = 12/3

X = 4

Y = 5

BC = FE:

3y - 7 = 8

Add 7 to both 2ides:

3y = 15

Divide both sides by 3:

y = 15/3

y = 5