Mathematics: Check the attachment for the info. I would give

(6^2*6^(1/2))^(1/3)(6^(5/2))^(1/3)6^(5/6)...

Check the attachment for the info. I would give

Ответ:

robert7248

17.03.2022

Mathematics

1) 0.9 as fraction is: $\mathbf{\frac{9}{10}}$

2) Solve for c =4 for the equation $2 \times (c^2-5)$ we get 22

3) t = 64

4) p=3.15

5) Volume of Cuboid = 160 m³

6) x =9

Step-by-step explanation:

1) Write as fraction: 0.9

For writing the fraction, Since we have decimal point at tent's place so we can write it as: $\frac{9}{10}$

So, 0.9 as fraction is: $\mathbf{\frac{9}{10}}$

2) Solve for c =4

$2 \times (c^2-5)$

Put c = 4 and find the answer

$2 \times (c^2-5)\\Put\:c=4\\=2\times ((4)^2-5)\\=2\times (16-5)\\=2\times(11)\\=22$

So, Solve for c =4 for the equation $2 \times (c^2-5)$ we get 22

3) $\frac{t}{4}=16$

We need to find value of t

Multiply both sides by 4

$4\times\frac{t}{4}=16\times 4\\t=64$

So, we get t = 64

4) 2.4p=7.56

We need to find value of p

Divide both sides by 2.4

$\frac{2.4p}{2.4}=\frac{7.56}{2.4}\\p=3.15$

So, we get p=3.15

5) Find Volume of Cuboid

The formula used is: $Volume\:of\: Cuboid=Length\times Breadth \times Height$

We have Length = 4, Breadth = 8 and Height = 5

Putting values and finding volume:

$Volume\:of\: Cuboid=Length\times Breadth \times Height\\Volume\:of\: Cuboid=4\times 8 \times 5\\Volume\:of\: Cuboid=160$

So, Volume of Cuboid = 160 m³

6) 3x=27

We need to find value of x

Divide both sides by 3

$3x=27\\\frac{3x}{3}=\frac{27}{3}\\x=9$

We get x =9

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