memeE15

15.08.2020 • 

Mathematics

company claims that the mean monthly residential electricity consumption in a certain region is more than kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of residential customers has a mean monthly consumption of kWh. Assume the population standard deviation is kWh. At , can you support the claim? Complete parts (a) through (e). (a) Identify and . Choose the correct answer below. A. : : (claim) B. : (claim) : C. : : (claim) D. : (claim) : E. : (claim) : F. : : (claim) (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical values are nothing. B. The critical value is 2.33. Identify the rejection region(s). Select the correct choice below. A. The rejection regions are z and z. B. The rejection region is z. C. The rejection region is z.

Ответ:

TheOriginal2x

09.06.2021

Mathematics

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Step-by-step explanation:

a )

sample mean = sum total of given data / no of data

= 415.35 / 20 = 20.76

To calculate the median we arrange the data in ascending order and take the average of 10 th and 11 th term .

= 20.50 + 20.72 / 2

= 20.61

b ) To calculate the 10% trimmed mean , we neglect the largest 10% and smallest 10 % data and then calculate the mean . Here we neglect the first two smallest and last two greatest

(18.92 + 19.25 + 22.43 + 22.85) / 16

= 20.74

c )

We can easily plot the data on number line from 17 to 24

d )

Maximum value of data set = 23.71 and minimum value is 18.04

mean is 20.76 , median is 20.61 and trimmed mean is 20.74

They are between maximum and minimum values of given data . Hence there is no outliers .

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