Benthega

30.11.2020 • 

Mathematics

Consider a husband and wife with brown eyes who have 0.75 probability of having children with brown eyes, 0.125 probability of having children with blue eyes, and 0.125 probability of having children with green eyes.
(c) If they have 5 children, what is the probability that exactly 3 will have blue eyes?
(d) If they have 5 children, what is the probability that at least 3 will have green eyes?
(e) What is the probability that the first brown eyed child will be child number 3?

Ответ:

goobert

27.11.2021

Mathematics

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Step-by-step explanation:

3x - 2y = –9

3x−2y+2y=−9+2y

3x=2y−9/3x^3

=2y−9/3

x=2/3y−3

4x + 3y = 22

4x+3y+−3y=22+−3y

4x=−3y+22

4x4

=−3y+22/4

x=−3/4y+11/2

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