Mathematics: Consider the function f(x) = 20/√x and its second-degree polynomial p2 (x) = 20 - 10(x-1) + 7.5(x-1)^2 at x=0.8. compute the value of f(0.8) and p2 (0.8). round your answer to four decimal places.(a) f(08) = 22.3607 p2(0.8) = 44.6000(b) f(08) = 22.3607 p2(0.8) = 22.3000(c) f(08) = 45.7214 p2(0.8) = 45.6000(d) f(08) = 21.3607 p2(0.8) = 21.3000(e) f(08) = 23.3607 p2(0.8) = 22.3000

Consider the function f(x) = 20/√x and its second-degree

Ответ:

AJRo

02.01.2022

f (0.8) = 22.3607 and $P_{2} (0.8) = 22.300$ .

Step-by-step explanation:

According to the statement, $f (x) = \frac{20}{\sqrt{x}}$ and $P_{2}(x) = 20 - 10 (x-1) + 7.5 (x-1) ^ 2$ . Based on these definitions, at x=0.8 produce:

$f (0.8) = \frac{20}{\sqrt {0.8}} = 22.3607$ . On the other hand, you have to:

$P_{2} (0.8) = 20 - 10 (0.8 -1) +7.5 (0.8 -1)^2$

$P_{2} (0.8) = 20 - 10 (-0.2) +7.5 (-0.2)^2 = 22.300$

Then, it can be affirmed that f (0.8) = 22.3607 and $P_{2} (0.8) = 22.300$ .

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Ответ:

hayden5928

27.12.2020

Mathematics

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