Mathematics: Determine any point in the third quadrant for which tan(α)=4. one valid point = ? ? for this angle, sin(α) = ? ? you for your

Determine any point in the third quadrant for

ale1910

10.03.2022

The point in third quadrant is: (-1,-4)

The value of sinα is $\dfrac{-4}{\sqrt{17}}$

Step-by-step explanation:

We are given that:

$\tan \alpha =4$

As we know that

$\tan \alpha =\dfrac{P}{B}$

Where P denotes the perpendicular and B denote the base of a right angled triangle formed by the help of the trignometric identity.

Thus means that P=4 and B=1

Hence the hypotenuse is given by H= $\sqrt{17}$ ( with the help of Pythagorean theorem)

so we could construct a triangle in third quadrant

Hence the point in third quadrant is (-1,-4).

Now corresponding to this point $\sin \alpha$ is given as:

$\sin \alpha=\dfrac{P}{H}$

⇒ $\sin \alpha=\dfrac{-4}{\sqrt{17}}$ (Negative sign is used as $\sin$ is negative in the third quadrant)

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ineedhelp2285

12.11.2022

ok see that 6x2-11x+3 put that and calculate it and thats the answer

Step-by-step explanation:

Hope this helps you :)

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