![cramirezorozco392](/avatars/1458.jpg)
cramirezorozco392
25.07.2021 •
Mathematics
Determine if the graph of y=x/x^2-4 is symmetrical with respect to the x-axis, the y-axis, or the origin.
a. about the x-axis
b. about the y-axis
c. about the origin
d. all of these
e. none of these
please help i’ll also rate brainliest
Solved
Show answers
More tips
- L Leisure and Entertainment Learn How to Knit with Needles: A Simple Guide for Beginners...
- C Computers and Internet Best Antivirus: How to Choose Protection for Your Computer?...
- L Legal consultation What Documents Are Required for a Russian Passport?...
- S Sport How to Choose Tennis Rackets?...
- H Health and Medicine AKDS Vaccination: Ensure Your Child s Safety...
- H Health and Medicine Naskol ko Opasen Ukus Kleshcha i Kak Ego Raspoznat...
- C Computers and Internet How to Delete Your Account on Odnoklassniki...
- H Health and Medicine What to Do When Your Jaw Locks Up?...
- G Goods and services What Are the Most Popular Services?...
Answers on questions: Mathematics
- M Mathematics WHATS THE ANSWER, I NEED IT QUICK, NO DOWNLOADED ANSWERS PUT THE REAL ANSWER THERE...
- H History I m seriously friends with benefits with my ex. We ve been kissing for the past two days, how do i get him back....
- M Mathematics Solve for b. -9b =27 b=...
- M Mathematics 6h+(-8.1d)-13+5d-3.2h...
Ответ:
9514 1404 393
c. about the origin
Step-by-step explanation:
The function is odd: replacing x with -x gives the negative of the function value:
f(-x) = -f(x)
Odd functions are symmetrical about the origin.
Ответ:
a) 95 miles
b) Chester
c) 194 miles
Step-by-step explanation:
Chart Reading
From the chart, we can know the relative distances from each place as follows:
a) From Hereford to Chester there are 95 miles
b) Kendal is 99 miles from Chester
c) If Ellen drives from Kendal to Hereford, passing by Chester, she will drive 99+95=194 miles
Note this last result is different from the direct distance from Kendal to Chester since the 201 miles are not specified if they are through Chester or not.