Mathematics: Determine the numerical value of y=(a+1)(b+1), knowing that ab= -6 and a+b=1

Determine the numerical value of y=(a+1)(b+1),

Ответ:

1kafran1

07.01.2022

Y=(a+1)(b+1)
ab=-6
a+b=1
a=1-b

(1-b)b=-6
-b^2+b+6=0
Δ=25, so b=3 or b=-2

Case 1: b=3, a+b=1, a+3=1, a=-2
y=(-2+1)(3+1)=-4
Case 2: b=-2, a+b=1, a-2=1, a=3
y=(3+1)(-2+1)=-4

So the value of y=(a+1)(b+1)=-4

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Ответ:

StitchBeach

07.04.2021

Mathematics

joe mama

Step-by-step explanation:

cause joe mama joe mama, duhhh

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Determine the numerical value of y=(a+1)(b+1), knowing that ab= -6 and a+b=1

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