Lonzo2
19.07.2019 •
Mathematics
Determine the type and number of solutions of x2 − 12x + 36 = 0.
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Ответ:
(a - b)^2 = a^2 - 2ab + b^2
a^2 = x^2
a = x
b^2 = 36
b = 6
x^2 -12x + 36 = (x - 6)^2 = 0
x = 6
There is one real solution.
Ответ:
Ответ:
9/10
Decimal Form:
0.9