Does 2 (x-1) + 6x=5(6x-1)+3 have infinite solutions

Short Answer No

Step-by-step explanation:

2(x−1)+6x=5(6x−1)+3

Step 1: Simplify both sides

2(x−1)+6x=5(6x−1)+3

(2)(x)+(2)(−1)+6x=(5)(6x)+(5)(−1)+3 Distribute

2x+−2+6x=30x+−5+3

(2x+6x)+(−2)=(30x)+(−5+3) Combine Like Terms

8x+−2=30x+−2

8x−2=30x−2

Step 2: Subtract 30x from both sides.

8x−2−30x=30x−2−30x

−22x−2=−2

Step 3: Add 2 to both sides

−22x−2+2=−2+2

−22x=0

Step 4: Divide both sides by -22.

−22x    0

=__

−22      -22

x=0

Hello!

To find the x-intercept given the equation of a line, we substitute y for 0 and solve for x.

0=4x²-9

We add 9 to both sides.

9=4x²

We find the square root of both sides.

3=4x

We divide both sides by 4.

x=3/4

Therefore, our x-intercept is 3/4.

I hope this helps!