michealjholley6211
12.12.2020 •
Mathematics
Each football costs the same amount, and each basketball costs the same amount. At the first store, the coach paid $110 for 5 footballs and 14 basketballs. At the second store, the coach paid $82.50 for 10 footballs and 6 basketballs. What was the cost in dollars of each basketball?
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Ответ:
$6.25
Step-by-step explanation:
Each football costs the same amount, and each basketball costs the same amount.
Let the cost of:
Footballs = f
Basketballs = b
Hence, we have the following system of equations
At the first store, the coach paid $110 for 5 footballs and 14 basketballs.
5f + 14b = 110
At the second store, the coach paid $82.50 for 10 footballs and 6 basketballs.
10f + 6b = 82.50
What was the cost in dollars of each basketball?
5f + 14b = 110 Equation 1
10f + 6b = 82.50Equation 2
We solve using Elimination method.
Multiply Equation 1 by 10 and Equation 2 by 5 to eliminate f
50f + 140b = 1100 Equation 3
50f +30b = 412.5Equation 4
Subtract Equation 4 from Equation 3
110b = 687.5
b= 687.5/110
b = $6.25
Therefore, the cost of one basketball in dollars = $6.25
Ответ:
oof thats hard mate
i'll think and come back