Mathematics: Elsa drove 245 m in 4.5 h. How many hours will it take her ti drive 650 m?

Elsa drove 245 m in 4.5 h. How many hours will - id245456734624, middlegirlrule6848

htahir2345

20.02.2022

The probability that the control chart would exhibit lack of control by at least the third point plotted is P=0.948.

Step-by-step explanation:

We consider "lack of control by at least the third point plotted" if at least one of the three first points is over the UCL or under the LCL.

The probability of one point of being over UCL=104 is:

$z=(X-\mu)/\sigma=(104-98)/8=6/8=0.75\\\\P(X104)=P(z0.75)=0.227$

The probability of one point of being under LCL=96 is:

$z=(X-\mu)/\sigma=(96-98)/8=-2/8=-0.25\\\\P(X$

Then, the probability of exhibit lack of control is:

P=P(X104)+P(X

The probability of having at least one point out of control in the first three points is:

$P(x\geq1)=1-P(0)\\\\P(x\geq1)=1- 0.052=0.948\\\\\\P(x=0) = \binom{11}{0} p^{0}q^{3}= 1*1*0.0515=0.0515\\\\$

The probability that the control chart would exhibit lack of control by at least the third point plotted is P=0.948.

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