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kathlynskare06
23.07.2019 •
Mathematics
Evaluate the following limit
lim x -> 0 sin x[cos (1/x^2) + sin (1/x^2)]
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Ответ:
The limit would present itself in the form
Obviously, you can't evaluate the two expressions
But since sine and cosine functions are always between -1 and 1, the sum of these will be a number between -2 and 2.
So, the limit presents itself in the form
Since you have the product of a quantity which tends to zero, sin(x), and a quantity which is bounded, cos(1/x^2)+sin(1/x^2).
Ответ:
4353
Step-by-step explanation:
54353