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26.06.2019 •
Mathematics
Evaluate the following logarithms. log12 144 = log15 1 = log3 ( 1 81 ) = log 0.00001 =
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Ответ:
Answer(s): (2,0,-4,-5)
log12 144 = 2
log15 1 = 0
log3 ( 1/ 81 ) = -4
log 0.00001 = -5
Ответ: