emmaraeschool
23.09.2019 •
Mathematics
Every evening jenna empties her pocket and puts pockets and puts her change in a jar. at the end of the week she counts her money. one week she had 50 coins all of them were dimes and quarters. when she added them up she had a total of $10.25 let d=number of dimes and q=numbers of quarters. how many quarters did jenna have?
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Ответ:
You then have the equations, x+y=50 and 0.1x+0.25y=10.25
You can now solve for y.
Solving for y,
x=50-y
0.1(50-y)+0.25y=10.25
5-0.1y+0.25y=10.25
y=35
Ответ:
35 quarters
Step-by-step explanation:
This problem is a system of equations solving problem.
"one week she had 50 coins all of them were dimes and quarters":
We can write the equation as
"when she added them up she had a total of $10.25":
Since value of quarter is 0.25 dollars and dime is 0.10 dollar and total value is 10.25, we can write the equation as
To solve both of this equation, we can multiply the first equation by -0.1 and then add the 2 equations and solve for q (shown below):
Hence, Jenna had 35 quarters.
Ответ:
the possible values of X,y are 45°,45°
405°,405°
Step-by-step explanation: