Every year in delaware there is a contest where people create cannons and catapults designed
to launch pumpkins as far in the air as possible. the equation y = 12 + 105x - 16x2 can be
used to represent the height, y, of a launched pumpkin, where x is the time in seconds that the
pumpkin has been in the air. what is the maximum height that the pumpkin reaches? how
many seconds have passed when the pumpkin hits the ground? (hint: if the pumpkin hits the
ground, its height is 0 feet.)
the pumpkin's maximum height is 184.27 feet and it hits the ground after 3.28 seconds.
the pumpkin's maximum height is 3.28 feet and it hits the ground after 6.67 seconds.
the pumpkin's maximum height is 184.27 feet and it hits the ground after 6.67 seconds.
the pumpkin's maximum height is 3.28 feet and it hits the ground after 184.27 seconds.

The maximum height = 184.27 feet and after 6.67 seconds the pumpkin comes back to the ground.

Step-by-step explanation:

The equation y = 12 + 105x - 16x2 ............ (1) The equation that models the relationship between the height, y, of the pumpkin, and x is the time of flight.

Hence, for the maximum height that the pumpkin reaches is given by the condition

Now, from the equation (1) we have  

105 - 32x = 0

⇒ x = 3.28 sec.

Therefore, the maximum height = 12 + 105 × 3.28 - 16(3.28)² = 184.27 feet (Answer)

Now, let it comes to the ground after x seconds.

Hence, 12 + 105x - 16x² = 0

Applying the Sridhar Acharya Formula,

the solution of the equation 16x² - 105x - 12 = 0 will be  

Secs.

{Neglecting the negative root} (Answer)

find 6 and plot it halfway for -5.5 and for 3 you already know

Step-by-step explanation:

Also the quadrant is probably IV/4

YW Hope you pass.