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zaire8
25.01.2020 •
Mathematics
Exercise 3.23 introduces a husband and wife with brown eyes who have 0.75 probability of having children with brown eyes, 0.125 probability of having children with blue eyes, and 0.125 probability of having children with green eyes. (a) what is the probability that their first child will have green eyes and the second will not?
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Ответ:
There is a 10.9375% probability that their first child will have green eyes and the second will not.
Step-by-step explanation:
We have these following probabilities:
0.75 probability of having children with brown eyes, 0.125 probability of having children with blue eyes, and 0.125 probability of having children with green eyes.
(a) What is the probability that their first child will have green eyes and the second will not?
There is a 0.125 probability a child will have green eyes and an 1-0.125 = 0.875 probability a child will not have green eyes.
So
0.125*0.875 = 0.109375
There is a 10.9375% probability that their first child will have green eyes and the second will not.
Ответ:
Answer
The answer will be 56.4
Explanation
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