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chapb75
06.03.2021 •
Mathematics
Express 0.361 as a fraction
where the 6 and 1 is recurring
Solved
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Ответ:
179/495
Step-by-step explanation:
x = 0.3616161 (I)
Multiply by 1000
1000x = 361.616161
Multiply (I) by 10
10x = 3.616161
1000x = 361.6161
10x = 3.6161 {Now subtract}
990x= 358
x = 358/990
x = 179/495
Ответ:
The equation is y = $72.99 + $28.45(x - 1), where y is the monthly charge and x is the month in which it is calculated.
Step-by-step explanation:
Step 1; First we need to establish a relation between the difference in costs. For the first month it cost $72.99, during the second month, it costs $101.44 and in the third month, it costs $129.89. Difference in rates
Second months rate - First months rate = $101.44 - $72.99 = $28.45
Third months rate - Second months rate = $129.89 - $101.44 = $28.45.
So for every consecutive month, the charges increase by $28.45
Step 2; Now we develop an equation,
y = $72.99 + $28.45(x - 1), where y is the charge that month and x is the month in which it is calculated.
For x = 1, y = $72.99 + $28.45(1 - 1) = $72.99 + $28.45(0) = $72.99,
For x = 2, y = $72.99 + $28.45(x - 1) = $72.99 + $28.45(2 - 1) = $101.44,
For x = 3, y = $72.99 + $28.45(3 - 1) = $72.99 + $28.45(3-1) = $129.89.
So this is the equation to calculate the cost y the mobile provider charges in month x.