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Clark1212
05.07.2019 •
Mathematics
F(x)=t-2(x+4)^2 where t is the constant. if f(-8.3)=f(a) and a > 0 what is the value of a ?
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Ответ:
We are given the equation:
F (x) = T – 2 (x + 4)^2 ---> equation 1
Since we know that f (-8.3) = f(a) and a>0, therefore from equation 1 we can generate that:
(x + 4)^2 = (a + 4)^2
(-8.3 + 4)^2 = (a + 4)^2
(-4.3)^2 = (a + 4)^2
(a + 4)^2 = 18.49
a + 4 = 4.3
a = 0.3
Ответ:
t= 28
Step-by-step explanation:
Isolate t by dividing both sides by 2.