Mathematics: Factor the polynomial 4n^3+20n^2-64n-320

Factor the polynomial 4n^3+20n^2-64n-320 - id43202643202129555, violetagamez2

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dbn4everloved

01.01.2022

$4n^3+20n^2-64n-320\\\\=\boxed{4n^2}\cdot n+\boxed{4n^2}\cdot5+\boxed{-64}\cdot n+\boxed{-64}\cdot5\\\\=\boxed{4n^2}(n+5)-\boxed{64}(n+5)\\\\=(n+5)(4n^2-64)\\\\=(n+5)(4\cdot n^2-4\cdot16)\\\\=(n+5)\cdot4(n^2-16)\\\\=4\cdot(n+5)(n^2-4^2)\ \ \ |use:a^2-b^2=(a-b)(a+b)\\\\\boxed{=4(n+5)(n-4)(n+4)}$

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Ответ:

anytka21ovxqoa

06.04.2023

Mathematics

The answer is B. Fabiana has completed the same amount of the course as Samantha because 6/15=8/20. Both fractions reduce to 2/5. Therefore, they are equivalent.

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Factor the polynomial 4n^3+20n^2-64n-320

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