Mathematics: Factoring binomials with the difference of squares

Factoring binomials with the difference of squares

infoneetusinghoyg22o

27.11.2021

$F(x,\lambda) = 1-e^{2x}$ for $x\geq0$

and $F(x,\lambda) = 0$ for

Step-by-step explanation:

Remember that the CDF of an exponental random variable is given by

$F(x,\lambda) = \left \{ {{1-e^{\lambda x} \ \ \ \ \ x\geq 0} \atop {0} \ \ \ \ \ \ \ \ \ \ \ x$

where $\lambda$ is the parameter. In this case $\lambda = 2$ so, for this case

$F(x,\lambda) = \left \{ {{1-e^{2x} \ \ \ \ \ x\geq 0} \atop {0} \ \ \ \ \ \ \ \ \ \ \ x$

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