gummybear0
15.08.2019 •
Mathematics
Factoring trinomials; i’m a little confused on this question ; (
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Ответ:
is the answer.
If you multiply it out you'll get the original trinomial
-10 and +9 add up to -1, the coefficient of the middle term. They also multiply to -90, which is the last term.
Ответ:
(x + 9)(n - 10)
Step-by-step explanation:
This trinomial is of the form
x^2 + ax + b
There is no number multiplying x^2.
To factor a trinomial of this type, set up two sets of parentheses:
( )( )
Place the variable inside each set of parentheses on the left side.
(x )(x )
Now look for two numbers that multiply to "b" and add to "a."
Place those two numbers inside the two sets of parentheses on the right side. Include + for a positive number and - for a negative number.
Let's work out your problem.
Factor n^2 - n - 90.
We see that there is no number multiplying the 2nd degree term since we have only n^2, not 2n^2 or 3n^2, etc.
We set up two sets of parentheses and place the variable n on the left side of each.
(n )(n )
Now we need two numbers that multiply to "b" and add to "a". Notice above, in x^2 + ax + b that b is the term that is just a number. "a" is the coefficient of the x-term. In your trinomial, n^2 - n - 90, a = -1 and b = -90. We need two numbers that multiply to -90 and add to -1. Since the two numbers must multiply to a negative number, -90, we must have a positive number and a negative number. 9 and -10 do multiply to -90. Also 9 and -10 add to -1. Now just place 9 and -1 in the parentheses on the right side. Include a "+" with the 9 and the negative sign with the 10.
(n + 9)(n - 10)
Ответ:
(-7) + (-14) = -21
(-7)*(-14)=98