Fast ! 20 points ! which is equivalent to \sqrt[3]{8}^{\frac{1}{4}x} ? a. 8^{\frac{3}{4}x} b. \sqrt[7]{8}^{x} c. \sqrt[12]{8}^{x} d. 8^\frac{3}{4x}

The usual convention is to write . So

and the answer is C.

Step-by-step explanation:

Given: GCF of two numbers is . neither number is divisible by the other.

To Find: smallest of these two number.

Solution:

As GCF of two numbers is , both number are divisible by .

Prime factor of

multiples of are

GCF of all three multiples is ,

Here and are the two multiples whose GCF is and neither is divisible by other

Hence the smallest of two is , the answer is