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boneyke3720
31.03.2020 •
Mathematics
Find all zeros and write in factored form
(x-5)(3x^2-8x+6) =0
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Ответ:
x = 5, 4/3+i√2/3, 4/3-i√2/3.
Step-by-step explanation:
(x-5)(3x^2-8x+6) =0
This is in factored form already. 3x^2 - 8x + 6 cannot be factored, it is prime.
One zero is x = 5.
3x^2-8x+6 = 0 Using the quadratic formula:
x = [8 +/- sqrt (64 - 4*3*6]) / 6
x = 4/3 +/- sqrt (-8) / 6
x = 4/3 +/- 2sqrt2 i / 6
x = 4/3 +/- i√2 / 3.
Ответ:
Step-by-step explanation:
Step 1 Given 0 times 2 = 0
Step 2 (-4+4)2=0
Step 3 Use The Distributive property
Step 5 Subtract 8 from both sides
Step 6 -4 times 2 = -8