Find an equation of the tangent line to the graph of y=f(x) at x=a f(x) = (x + x + 1)(3x² + 2x - 1), a = 1

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Ответ:

potato3999

10.09.2022

Mathematics

The value of $(\frac{f}{g})(5)$ is $\frac{27}{35}$

Explanation:

Given that f(x)=7+4x and g(x)=7x

The value of $(\frac{f}{g})(5)$ :

The value of $(\frac{f}{g})(5)$ can be determined by substituting x = 5 in the functions f(x) and g(x) and then dividing the terms, we get, the value of $(\frac{f}{g})(5)$

Thus, we have,

$(\frac{f}{g})(5)=\frac{f(5)}{g(5)}$

Substituting the value of x = 5 in the functions f(x) and g(x), we get,

$(\frac{f}{g})(5)=\frac{7+4(5)}{7(5)}$

Simplifying the terms, we have,

$(\frac{f}{g})(5)=\frac{7+20}{35}$

Adding the terms in numerator, we have,

$(\frac{f}{g})(5)=\frac{27}{35}$

Thus, the value of $(\frac{f}{g})(5)$ is $\frac{27}{35}$

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