Find length of AC? Help please

b

Step-by-step explanation:

i hope you pass you your grade

D

Step-by-step explanation:

cos(theta) = B/H

cos(51)= AC/58

AC=36.5

36.5 = AC

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj side/ hypotenuse

cos A = AC / AB

cos 51 = AC /58

58 cos 51 = AC

36.50058 = AC

Rounding to the nearest tenth

36.5 = AC

SSS

Step-by-step explanation:

We are given a triangle XYZ with side lengths 12, 14, and 16. We are also given another triangle RQS with side lengths 3, 3.5, and 4. In order to see if they're similar, we must check whether corresponding sides have the same ratio.

The shortest side of each triangle correspond to each other; the same can be said about the medium-length sides and the longest sides. In other words, XZ = 12 corresponds with SR = 3; YX = 14 corresponds to RQ = 3.5; and ZY = 16 corresponds to QS = 4. Let's find the common ratio:

XZ / SR = 12 / 3 = 4

YX / RQ = 14 / 3.5 = 4

ZY / QS = 16 / 4 = 4

Thus, since the ratios are all 4, we can say that the two triangles are similar by the SSS (side-side-side) Similarity Theorem.

Hope this helps!