Find the 12th term of the arithmetic sequence given a3=116 and a7=180

Step-by-step explanation:

nth term = a +(n-1)d

a3 = 116 ;   a + 2d = 116 (i)

a7 = 180;   a + 6d = 180 (ii)

multiply (ii) by -1. so a will be eliminated

           a + 2d = 116 (i)

(ii)*-1    -a - 6d = -180 (ii)   { Now add the two equations}

              - 4d = -64

                   d = -64/-4

                  d = 16

Plug in the value of d in equation (i),

a + 2*16 = 116

a + 32 = 116

        a = 116 - 32

        a = 84

12th term = 84 + 11* 16 = 84 + 176 = 260

yes

Step-by-step explanation:

square root of 4 you mean?

square root of 4 is 2

2 can be written as 2/1

(it could be written as square root(4))/1

or it could be the simplest form of a more complex fraction

square root of 4 can also be written as 4^(1/2)

if you mean (square root(square root(square root(square root(x

that could be written as x^(1/2)^(1/2)^(1/2)^(1/2) which I think is equal to x^1/16 or 16'th root of x