Mathematics: Find the area of a regular polygon that has 15 sides and a perimeter 120ft. Please answer fast

Find the area of a regular polygon that has 15

hayleydawn

18.03.2022

Let 's' be the length of a side of the polygon.

Then,

perimeter = 15s

or, 120 = 15s

or, s = 8ft.

The area of regular polygon having 'n' number of sides with each of length 's' is given by:

A = $[{\frac{s}{2tan(\frac{180}{n}) }} (n)(s)]^{2}$

According to question,

s=8ft, n = 15

Therefore, Area = $[\frac{8}{2tan(\frac{180}{15}) }(15)(8)] = [\frac{480}{2tan(12)}] = (240cot12)$ ≈1129.11sq. ft

0,0(0 оценок)

heinslice3

07.07.2022

y = -1x - 9Explanation:

First, we’ll need to find the slope.

(-5,-4) (-2,-7)

m = $\frac{y_{2} - y_{1} }{x_{2} - x_{1} }$

m = $\frac{-4 - (-7)}{-5-(-2)}$

m = $\frac{-3}{3}$

m = -1

Next, substitute these values into the point slope equation:

y - $y_{1}$ = m(x - $x_{1}$ )

y - (-7) = -1(x - (-2))

y + 7 = -1(x + 2)

Now, convert to slope intercept form (y = mx + b):

y + 7 = -1x -2

-7 -7

y = -1x - 9

0,0(0 оценок)